The expected (mean) life of a particular type of light bulb is 1000 hours with a standard deviation of 50 hours. The life of this world is normally distributed what is the probability that a randomly selected bulb would last fewer than 940 hours?

11.5%

Step-by-step explanation:

To solve this problem, we can use the knowledge that there are z score tables that calculate probabilities based on z scores. Thus, we must calculate the z score.

The z score formula is , where x is the value, m is the mean, and s is the standard deviation. We can then plug our values in to get as our z score. Plugging this into a table where table values represent the area to the left of the z score (as we want to calculate everything under 940), we get 0.115, or 11.5% as our answer

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)