What is the maximum value of the objective function, P, with the given constraints? P=25x+45y 4x+y≤16 x+y≤10 x≥0 y≥0

the maximum is 450 and the minimum is 0.

Step-by-step explanation:

We know that:

P(x, y) = 25*x + 45*y

First, is easy to see that as x and y increase, also does the value of P(x, y)

So we just need to find the largest and smallest possible values of these variables. We also can notice that the variable y is being multiplicated by a larger coefficient than x, so we prioritize larger values of y when we can.

We know that:

4x+y ≤ 16

x + y ≤10

x≥0

y≥0

Let's start with the second inequality, let's solve this for y:

y ≤ 10 - x

and from the first one we get:

y ≤ 16 - 4*x

Just to show that maximizing x does not work, let's do it:

from the second one, knowing that the minimum value of y is y = 0

we have that:

0 ≤ 16 - 4*x

Here the maximum value that y can take is x = 1

0 ≤ 16 - 4*1 = 0

So we can have the combination y = 0 and x = 1, when we maximize x (here we can see that we should not maximize x)

in this case we get:

P(1, 0) = 25*1 + 47*0 = 25

let's write again our inequalities:

y ≤ 10 - x

y ≤ 16 - 4*x

If now we take the minimum value of x, x = 0, we get:

y ≤ 10

y ≤ 16

Because the first one is more restrictive, we know that the maximum value that y can take (when x = 0) is y = 10

in this case we get:

P(0, 10) = 25*0 + 45*10 = 450

As expected, here is the actual maximum for the given restrictions.

For the minimum, we just need to take the two lowest possible values of x and y, which are the two given by the equalities on:

x≥0

y≥0

The smallest values are:

x = 0

y = 0

Replacing that in the equation we get:

P(0, 0) = 25*0 + 47*0 = 0

So the maximum is 450 and the minimum is 0. (with the given restrictions)

the  office resources  are the human, physical and financial  resources  which are utilized for performing all the activities in order to achieve the organizational objectives.

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step-by-step explanation: