Write two polynomials q(x) and p(x) such that the degree of both q(x) and p(x) is 3 but degree of the polynomial q(x) + p(x) is 1.​

P(x)Q(x)= (x3 − x2 + x − 1)(3x3 − 2x2)

= x3(3x2 − 2x2) − x2(3x3 − 2x2) + x(3x3 − 2x2) − (3x3 − 2x2)

= 3x6 − 2x5 − 3x5 + 2x4 + 3x4 − 2x3 − 3x3 + 2x2

= 3x6 − 5x5 + 5x4 − 5x3 + 2x2

no association

step-by-step explanation:

if you have eyes and you can use them efficiently you can see that it just looks like random dots like do a line of best fit and like they're so spread out it's such a weak association you might as well consider it nonexistent

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)