A bag contains 3 red marbles, 7 blue marbles and 5 green marbles. If three marbles are drawn out of the bag, what is the probability that all three marbles drawn will be green?

1/3

Step-by-step explanation:

since the total number of marbles are 3+7+5=15

and the number of green marbles=5

so probability of three marbles drawn being green=5/15=1/3

6/91

Step-by-step explanation:

P(all are green)= P(GGG)

P(G)×P(G)×P(G)

5/15 × 4/14 × 3/13 = 6/91

NOTE: the total marbles in the bag decreased as the green marbles were picked

the answer is here: : )

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step-by-step explanation: