One bag of marbles contains 2 black , 3 red , and 5 white marbles . A second bag contains 3 white and 2 black marbles . What is the probability of selecting one marble from each bag and that they are not both black. Please help!!

NOT BOTH BLACK = 1-2/25 = 23/25

Step-by-step explanation:

Bag 1 : 8 non-black out of 10

P(1) = 8/10

Bag 2: 3 non-black out of 10

P(2)=3/5

Probability of both independent events happening can be calculated using the multiplication rule

P(1) and P(2) = P(1)*P(2) = 8/10 * 3/5 = 24/50 = 12/25 (both are not black, or none is black)

Interpretating not both black meaning at most one black, then

we calculate the probability of both are black,

P(1) = 2/10

P(2) = 2/5

Probability that both balls are black can be calculated using the multiplication rule

P(1) and P(2) = 2/10 * 2/5 = 2/25

Probability that NOT BOTH BLACK = 1-2/25 = 23/25, i.e. at most one black

38.5

step-by-step explanation:

lets say, first number = r

second number = 3r+7

total = 49

(r)+(3r+7)= 49

4r+7 = 49

4r = 42

r = 42/4

r= 10.5

3r+7 = 3(10.5)+7 = 38.5

hope this

x > 1.3

step by step:

8.5−0.9x> 9.8−1.9x

step 1: simplify both sides of the inequality.

−0.9x+8.5> −1.9x+9.8

step 2: add 1.9x to both sides.

−0.9x+8.5+1.9x> −1.9x+9.8+1.9x

1x+8.5> 9.8

step 3: subtract 8.5 from both sides.

1x+8.5−8.5> 9.8−8.5

1x> 1.3

step 4: divide both sides by 1.

1x/1 > 1.3/1