The systolic blood pressure (BP) of adults in the USA is nearly normally distributed with a mean of 121 and standard deviation of 16 . Someone qualifies as having Stage 2 high blood pressure if their systolic blood pressure is 160 or higher. (a) Around what percentage of adults in the USA have stage 2 high blood pressure

Around 0.73% of adults in the USA have stage 2 high blood pressure

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean and standard deviation , the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 121 and standard deviation of 16.

This means that

Around what percentage of adults in the USA have stage 2 high blood pressure

The proportion is 1 subtracted by the p-value of Z when X = 160. So

has a p-value of 0.9927.

1 - 0.9927 = 0.0073

0.0073*100% = 0.73%

Around 0.73% of adults in the USA have stage 2 high blood pressure

i think it will be zero as slope has a formula of difference between initial and final distance divided by itz time interval

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