Answers: 2
and then take the inverse sin of both sides to get
(the inverse sin undoes the sin on the right). Now we need to look on our unit circle to find the angles where 
is positive. There are 2 places. Sin is positive in both QI and QII. The angles are
. Therefore, our 2 equations are
and 
. Solving the first equation:
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Solve each equation for 0 ≤ θ 2π -2√2=-4sin 2θ...
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