Suppose that γ is an angle with csc γ = -11/10 and γ is not in the third quadrant. Compute the exact value of cot γ. You do not have to rationalize the denominator.

Draw your right triangles.

sin(g) = -3/4: you need to draw the point (x, y) such that y = -3, x < 0, and x2 + (-3)2 = 42

Then cos(g) = x/4, tan(g) = -3/x, csc(g) = -4/3, sec(g) = 4/x, and cot(g) = -x/3

The others are done similarly: use the info given to figure out the (x, y) point, and derive trig ratios from them,

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step-by-step explanation:

answer: all of the odd numbers were opened

the first person was the one that was opening all of the lockers. since one is odd, this causes all of the odd number lockers to be opened in the end.