In Ottawa you can ride on a tour bus for a fixed price plus a variable amount that depends on the length of the trip. the variable cost is $2/km and 20km trip cost $55 Determine the equation relating cost, C, in dollars, and distance, d, in kilometers.

C = 2d + 15

Step-by-step explanation:

$2 per km, so $40 for 20km.

55-40 is 15 so $15 is a fixed price.

Hence, C = 2d + 15

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b

step-by-step explanation:

most likely the answer is a.

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