A) Model this situation with a linear system: To rent a car, a person is charged a daily rate and a fee for each kilometre driven. When Chena
rented a car for 6 days and drove 320 km, the charge was $286.00. When she rented the same car
for 10 days and drove 900 km, the charge was $605.00.
b) Determine the daily rate and the fee for each kilometre driven.

The daily rate is $ 29 and the fee for each kilometer driven is $ 0.35.

Step-by-step explanation:

Since to rent a car, a person is charged a daily rate and a fee for each kilometer driven, and when Chena rented a car for 6 days and drove 320 km, the charge was $ 286.00, while when she rented the same car for 10 days and drove 900 km, the charge was $ 605.00, to determine the daily rate and the fee for each kilometer driven the following calculation must be performed:

286 = 6 days and 320 km

320/6 = 53,333 km

286/6 = $ 47,666

Thus, the value of 1 day and 53,333 km is $ 47,666.

605 = 10 days and 900 km

900/10 = 90 km

605/10 = $ 60.5

Thus, the value of 1 day and 90 km is $ 60.5.

90 - 53,333 = 36,666

60.5 - 47.666 = 12.833

12,833 / 36,666 = value per kilometer traveled

0.35 = value per kilometer traveled

(286 - (0.35 x 320)) / 6 = X

(286/112) / 6 = X

174/6 = X

29 = X

(605 - (0.35 x 900)) / 10 = X

(605 - 315) / 10 = X

290/10 = X

29 = X

Therefore, the daily rate is $ 29 and the fee for each kilometer driven is $ 0.35.

here you hope this .

step-by-step explanation:

hypotenuse = √(15² + 8²)

=  √(225 +64)

=  √(289) = 17

sin(x) = cos(y) = 8/17

they are identical so long as you are doing the sine of one angle and the cosine of the only other angle that isn't the right angle.

ik how do do this just give me a few minutes and i will give it to