What is the average rate of change of the function f(x)=2x^2+x+5 over the interval -2<x<2? A. -4
B. -1
C. 1
D. 4​

C

Step-by-step explanation:

The average rate of change of f(x) in the closed interval [ a, b ] is

Here [ a, b ] = [ - 2, 2 ] , then

f(b) = f(2) = 2(2)² + 2 + 5 = 8 + 2 + 5 = 15

f(a) = f(- 2) = 2(- 2)² + (- 2) + 5 = 8 - 2 + 5 = 11 , then

average rate of change = = = 1 → C

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°