Can someone help me with this question please? If f(x) = -2(x-3)^2 - 6, Find
g(x)=f(x) -1
g(x)=f(x - 2) + 5

1/

g(x)=f(x)-1=[-2(x-3)^2-6]-1=-2(x-3)^2-7

2/

g(x)=f(x-2)+5=-2(x-2-3)^2-6=-2(x-5)^2-6

2x^2+5x+17

your welcome. : )

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