A spring with a 10-kg mass and a damping constant 15 can be held stretched 1 meters beyond its natural length by a force of 2 newtons. Suppose the spring is stretched 2 meters beyond its natural length and then released with zero velocity. In the notation of the text, what is the value c^2 - 4mk? m^2 kg^2/sec^2. Find the position of the mass, in meters, after t seconds. Your answer should be a function of the variable t of the form c_1 e^alpha t + c_2 e^beta t where alpha = (the larger of the two) beta = (the smaller of the two) c_1 = c_2 =.