Mike just hopped on the edge of a merry-go-round. What are his linear and angular speeds if the diameter of the merry-go-round is 14 feet and it takes 6 seconds for it to make a complete revolution? Round the solutions to two decimal places.

Step-by-step explanation:

Given that,

The diameter of the merry-go-round, d = 14 feet

Time taken, t = 6 seconds

Radius, r = 7 feet

The linear speed of the merry-go-round is given by :

Also,

Where

is the angular speed

So,

Hence, his linear and angular speeds are 7.33 m/s and 1.04 rad/s.

for this case we have by definition, if two lines are perpendicular, then the product of their slopes is -1.

then, given the following line:

so,

we are looking for m_ {2}:

then, the line is given by:

we find "b" replacing the given point:

finally, the equation is:

option c

hi there!

question 1 answer: p/q can be terminating when q = 5^m * 2^n

question 2 answer: -1 and -1

question 3 answer: -4

question 4 answer: 5/12

hope this : )