How do you solve this?

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Explanation:

If we plugged (x,y) = (0,8) into the first inequality, then we get

y < x^2+6

8 < 0^2+6

8 < 0+6

8 < 6

which is false. So we can rule out choice A.

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Trying choice B leads us to

y < x^2+6

2 < 4^2+6

2 < 16+6

2 < 22

That last statement is true, so the first inequality is true for (x,y) = (4,2)

Let's try the other inequality

y > x^2-4

2 > 4^2-4

2 > 16-4

2 > 12

That's false. Since one of the inequalities is false (it doesn't matter which one), this means the entire system is false. We cross choice B off the list.

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Now onto choice C

You should find that y < x^2+6 becomes -4 < 10 after plugging in (x,y) = (-2,-4). Since -4 < 10 is true, we move onto the next inequality.

The inequality y > x^2-4 becomes -4 > 0 after plugging in those mentioned x,y values. The inequality -4 > 0 is false.

We cross choice C off the list.

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The only thing left is choice D. It has to be the answer.

Let's find out if we get true inequalities when plugging in (x,y) = (2,6)

y < x^2+6

6 < 2^2+6

6 < 10 ... true

and

y > x^2-4

6 > 2^2-4

6 > 4-4

6 > 0 .... also true

Both inequalities are true, so the entire system is true. Therefore, (x,y) = (2,6) is one of the infinitely many solutions to this system.

Choice D is confirmed as the answer

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Refer to the diagram below. I've graphed the two dashed boundary curves and the shaded region between. This region is above the y = x^2-4 curve, and below the y = x^2+6 curve. So we're ignoring the stuff above the y = x^2+6 curve.

Points A through D represent the four answer choices in the order given. We see that point D is the only point in the shaded region, so that visually confirms we have the correct answer.

Note: points on the dashed boundaries do not count as solutions.

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x

in the math equation 8 x 7 = 56, the 8 and the 7 are both factors of 56, since in this lesson we will use square tiles to figure out the factors of a whole find as many different arrays as you can, but follow one important rule: all the rows must have the i can make two rows of nine, so 2 and 9 are both factors of 18.

step-by-step explanation: