Topic - Solving Linear Inequalities. Q - A vehicle with an empty fuel tank has a mass of 1050kg. One litre of petrol has a mass of 737g. What is the minimum amount of whole litres of petrol that would cause the total mass to exceed 1100kg?

Please help me. ​

The minimum balance is 68 liters

Step-by-step explanation:

Let the number of liters of petrol required be x

Given that  One litre of petrol has a mass of 737g, x liters will have a mass

= 0.737x kg

Recall that 1 kg = 1000g

Since the empty fuel tank has a mass of 1050kg

The total mass = 1050 + 0.737x IN kg

For the total mass to exceed 1100kg, then

1050 + 0.737x > 1100

0.737x > 1100 - 1050

0.737x > 50

Divide both sides by 0.737

x > 50/0.737

x > 67.84260516

answer: the answer is 30 miles per hour.

ft/s -> mphmph = ft/s 1.466667mph = 44 divided by 1.466667mph = 30.00000

- r3ktforgood ☕

45

step-by-step explanation:

to find a percentage, add a decimal in front and multiply it by the other number.

.25 times 180= 45