PLS HELP ILL GIVE U BRAINLIST A vector is 2.5 kilometers per hour at a bearing of of 50° West of North.

Find the magnitude of its vertical component.

lyl = v sin ©

A. lyl = - 1.9
B. lyl = 1.6
C. lyl = 2.5
D. lyl = 50°​

B. |y| = 1.6

A sketch of the vector is attached to this response.

As shown, the vector lies on the second quadrant and its horizontal and vertical components are given by x and y respectively.

Where;

|x| = v cos θ              -----------------(i)

|y| = v sin θ               -----------------(ii)

and

v = magnitude of the vector = 2.5km/hr

θ = angle that the vector makes with the +x axis = 90° + 50° = 140°

To get the magnitude of the vector's vertical component

Substitute these values into equation(ii) as follows;

|y| = 2.5 sin 140°

|y| =  2.5 x 0.6428

|y| = 1.607

|y| ≅ 1.6 km/hr

Therefore, the vertical component of the vector has a magnitude of 1.6 km/hr.