If m = 0, then prove that a^12 - 18a^6 + 1= 0, when m = a^2 - √5a + 1

g = (2, 2)

step-by-step explanation:

given the ratio is 1 : 1 then f is the midpoint of eg

let the coordinates of g = (x, y)

using the midpoint formula

(0 + x) = 1 ( multiply both sides by 2 )

0 + x = 2 ⇒ x = 2

similarly

(4 + y) = 3 ( multiply both sides by 2 )

4 + y = 6 ( subtract 4 from both sides )

y = 2

coordinates of g = (2, 2)

c 1 hour

step-by-step explanation:

m = 2e

m = 2 so 2 = 2e

1 = e