Help, please! With workings too! I'm thinking of a 3-digit number.
When it is divided by 9, the remainder is 3
When it is divided by 2, the remainder is 1
When it is divided by 5, the remainder is 4
What is my number?

3-digit number is abc. ( just call it)

abc= 9d + 3, meaning abc = 3e

abc = 2k + 1, meaning abc is an odd number

abc = 5t + 4, meaning c = 9 ( because abc is an odd number so c can not be 4)

so a+b must be equal 3.

abc can be 309, 219, 129

answer: solve 5\cdot 2^x=2405⋅2  

x

=2405, dot, 2, start superscript, x, end superscript, equals, 240.

solution

to solve for xxx, we must first isolate the exponential part. to do this, divide both sides by 555 as shown below. we do not multiply the 555 and the 222 as this goes against the order of operations!

\begin{aligned} 5\cdot 2^x& =240 2^x& =48 \\ \end{aligned}  

5⋅2  

x

2  

x

​    

=240

=48

​

step-by-step explanation: