Its due in 20 mins
Will mark brainliest​

a) 20 km away fro the starting point.

b) The bearing from P to R is 80°.

c) Q is 60 km North P.

d) Q is - 60 km west of P

Step-by-step explanation:

Stating Facts in the Question:

P to Q is 80 km and bearing 330°

It turned around, Q to R is 60 km and bearing 250°.

a) Picture a number line (Look at the first image)

You go 80 to the right. You turn around and go 60 to the left.

80 - 60 = 20

20 km away fro the starting point

b) Picture a number line (Look at the second image)

P to Q is bearing 330°

Q to R is 60 km is bearing 250°

P to Q is red

Q to R is blue

330° - 250° = 80°

The bearing from P to R is 80°

c) P to Q is 60 km

The plane went forward or North so the answer is 60 km.

Q is 60 km North P.

d) Q to P is 60 km

Q is not to the west of P

Q is - 60 km west of P

b. would be the answer : )

step-by-step explanation:

step 1: add -16x to both sides.

16x−4y+−16x=64+−16x  

−4y=−16x+64

step 2: divide both sides by -4.

−4y /-4 = -16x + 64/-4

answer:   y=4x−16

hope i'm right