Find three consecutive odd integers such that the sum of twice the first and three times the second is 55 more than twice the third.

Step-by-step explanation:

let the numbers be n,n+2,n+4

2n+3(n+2)=2(n+4)+55

2n+3n+6=2n+8+55

2n+3n-2n=63-6

3n=57

n=57/3=19

so numbers are 19,21,23

-19.333…

-18.333…

-17.333…

Step-by-step explanation:

First is x

Second is x+1

Third is x+2

2x+3(x+1)=2(x+2)-55

2x+3x+3=2x+4-55

5x+3=2x-51

5x-2x=-51-3

3x=-58

3x/3=-58/3

x=-19.333…

x+1=-19.333+1

=-18.333...

x+2=-19.333+2

=-17.333...

the correct answer is semicircle

step-by-step explanation:

the answer is semicircle because the shorter arc joining two points on the circumference of a circle is known as the minor arc, the larger arc is called the major arc, and a semicircle is a half circle, formed by cutting a whole circle along a diameter line.

hope i .

x is greater than 5

step-by-step explanation:

2x+7 is greater than 17

    -7                           -7

2x is greater than 10

divide by 2 each side

x is greater than 5