What is the perimeter of Quadrilateral ABCDwith vertices at A(−11, −6), B(−3, 0), C(1, 0), and D(1, −6)?

32 units

Step-by-step explanation:

the perimeter =

(1 -(-3)) +(0-(-6)) + (1 -(-11) + (√(12-4)²+6²)

= (1+3) +(0+6) +(1+11) +(√(64+36))

= 4+6+12 + 10

=32 units

cut 138 centimeters off

step-by-step explanation:

250-112 = 138

squares, rhombus, rectangles