A ball is thrown from a height of 40 meters with an initial downward velocity of 5 m/s. The ball's height h (in meters) after 1 seconds is given by the following. h - 40 - 51-57
How long after the ball is thrown does it hit the ground?
PA
Round your answer(s) to the nearest hundredth.
(If there is more than one answer, use the "or" button.)

0=40-10t-5t^2

t^2+2t-8=0

(t+4)(t-2)=0

t=-4 (not a solution) or t=2

after 2 seconds

Step-by-step explanation:

First, set h (height) to 0, since that is the height we'll be solving for (at the ground). Factor the right side of the equation and set each individual binomial equal to zero. Solve for x in both equations and you should be left with a negative answer and a positive one. There is no negative time, so choose the answer that is positive.

i would say b) is your answer

sorry if im wrong

step-by-step explanation: