If 2x + 3y = 12 and xy = 6, find the value of 8x^3 + 27y^3​

2x+3y=12

Step-by-step explanation:

cube on both sides,

(2x+3y)^3 =12^3

by the identity (a+b)^3= a^3 +b^3 +3ab(a+b)

here, 8x^3 + 27y^3 +3(6xy)(2x+3y) =12^3

putting the values which are given ,

8x^3 +27y^3 +3*(6*6)(12) = 1728

8x^3 + 27y^3 +1296 = 1728

8x^3 +27y^3 = 1728-1296

8x^3 +27y^3 =432

let's solve your equation step-by-step.

24−3x=−27

step 1: simplify both sides of the equation.

24−3x=−27

24+−3x=−27

−3x+24=−27

step 2: subtract 24 from both sides.

−3x+24−24=−27−24

−3x=−51

step 3: divide both sides by -3.

−3x

−3

=

−51

−3

x=17

answer:

x=17

step-by-step explanation:

mark brainliest and have a great day!