SUPER URGENT: What is the range of y = sinx in the interval - π ≤ x ≤ 0? -1 ≤ y ≤ 1
-1 ≤ y ≤ 0
0 ≤ y ≤ 1
y ≤ 1

-1 ≤ y ≤ 0

Step-by-step explanation:

here, we simply want to know the range of values for sin x over the given interval

The range of values for sin x are simply the values in which y will take over the given interval of x

let’s start with the value sine (-pi)

We have this as;

0

And the value of sin (0) = 0

Recall, between -pi and 0, we have (-pi/2)

so sin (-pi/2) = -1

Thus, we have the correct range of values as;

-1 ≤ y ≤ 0

c) yes, because of asa or aas