Josh graphed the function f(x)=-3(x-1)^2 +2. He then graphed the function g(x)=-3(x-1)2 -5 on the same coordinate plane. The vertex of g(x) is​

the graph of f(x) is {5 - (-2)) units, or 7 units, higher than that of g(x)

Step-by-step explanation:

The vertex form of a quadratic equation is y = a(x - h)^2 + k.  (h, k) represents the vertex.

Comparing the given f(x) = -3(x-1)^2 to the above general form, we see that h = 1 and k = 2.

Comparing the given g(x) = -3(x-1)^2 to the above general form, we see that h = 1 and k = -5.  

Thus, the x-coordinates of the vertex in both cases are the same:  1.  The y-coordinates differ:  for f(x), k = 2. and for g(x), k = -5.

Changing the k value translates the graph up or down.

In this case we see that the graph of f(x) is {5 - (-2)) units, or 7 units, higher than that of g(x).

e) none of the above because the measure of angle cba is 101°

5 x 14?

im new, sorry if this is wrong.

step-by-step explanation: