For this line 3x−4y−12=0, which statement is true? 1- The x-intercept is 4, and the y-intercept is 3. 2-The x-intercept is 4, and the y-intercept is -3 3-The x-intercept is 3, and the y-intercept is -4. 4-The x-intercept is 3, and the y-intercept is 4.

9514 1404 393

  2. The x-intercept is 4, and the y-intercept is -3

Step-by-step explanation:

The given equation is in general form. I find it easier to see the intercepts when the equation is written in standard form:

  3x -4y = 12

Setting y=0 and solving for x, we have the x-intercept:

  3x = 12   ⇒   x = 12/3 = 4

Setting x=0 and solving for y, we have the y-intercept:

  -4y = 12   ⇒   y = 12/-4 = -3

The x-intercept is 4; the y-intercept is -3.

the square root of what number? if you add that, then someone will probably answer the question.

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

~