The probability that a person has blue eyes is 16%. Three unrelated people are selected at random. a. Find the probability that all three have blue eyes b. Find the probability that none of the three have blue eyes c. Find the probability that one of the three has blue eyes

Step-by-step explanation:

All three have blue eyes.

P(1 has blue eyes) = 16/100 = 4/25

P(3 have blue eyes) = 4/25 * 4/25 * 4/25

P(3 have blue eyes ) = 64/15625

If you need the decimal answer, it is .004096

No one has blue eyes out of three

The probability for this is very large.

P(no blues) = 1 - 64/15625

P(no blues) = 15561/15625  

If you need the decimal answer, it is 0.996

One has blue eyes (the other two do not).

P(1 has blue eyes) = 16/100 * 84/100*84/100

P(1 has blue eyes) = 112896/1000000

P(1 has blue eyes) = 0.112896

answer: 16

step-by-step explanation: first you would add 6+6 which equals 12 then add 2+2 which equals 4. then add 12 + 4 which is 16.

hope this ^_^

7

step-by-step explanation: