Alguien me ayuda Gracias 1) Se lanza un dado la probabilidad de que caiga un número

mayor que 5 es: 26,66%

V o F

2) Se lanza un dado, la probabilidad de que caiga un número mayor que 2 es: 56,66%

V o F

3) En una caja hay 12 pelotas de igual tamaño, de las cuales 7 son azules y 5 blancas.

La probabilidad de que al extraer una esta sea blanca es: 40,66%

V o F

4) Un matrimonio desea tener 3 hijos. La probabilidad de obtener:

Dos varones y una hembra es: 47,5%

V o F

5) Un matrimonio desea tener 3 hijos. La probabilidad de obtener dos varones y dos hembras es: 50%

V o F

1) V

2) V

3) V

4) V

5) V

Step-by-step explanation:

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?