What is the exponential form for 7^√x^3

The exponential form of this would be (7x)^3/2

Step-by-step explanation:

The square root symbol is the same as writing raised to the 1/2. So we can rewrite the equation as:

[(7x)^1/2]^3

Then we can multiply the two exponents in this case giving us

(7x)^3/2

(√7)3=732

Explanation:

To write

(√7)3

in exponential form, one needs two identities - n√a=a1n

and (am)n=a(m×n)

which is true for all rational

m and n.

Hence,

(√7)3= (712)3

= 7(12×3)

= 732

(f - g)(x) = 5x^3 - 3

step-by-step explanation:

rearrange these functions vertically, with like terms in separate columns:

f(x) = 5x^3 - 2

g(x) =         +1

now subtract, column by column:

(f - g)(x) = 5x^3 - 3

step-by-step explanation:

the true statements are:

r = set of real numbers

n = set of natural numbers, 1,2,

w = n u{0} = {0,1,}