Suppose a triangle has two sides of lengh 32 and 35, and that the angle between these two sides is 120°. Which equation should you solve to find the length of the third side of the triangle? A: c^2=32^2 + 35^2 - 2(32) (35) cos120°
B: sin32/120 = sin35/b
C: c=32 + 35 - 2(32)(35)cos120°
D: c^2 =32^2 + 35^2 - 2(32)(35) sin120°
(NEED ASAP)
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g = (2, 2)

step-by-step explanation:

given the ratio is 1 : 1 then f is the midpoint of eg

let the coordinates of g = (x, y)

using the midpoint formula

(0 + x) = 1 ( multiply both sides by 2 )

0 + x = 2 ⇒ x = 2

similarly

(4 + y) = 3 ( multiply both sides by 2 )

4 + y = 6 ( subtract 4 from both sides )

y = 2

coordinates of g = (2, 2)

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

answer

you start with $5 and save $10 a week until you have at least $45wer

step-by-step explanation: