∆ABC has coordinates A(3, 1), B(5, 5) and C(4, 1). After a translation, the coordinates of A' are (0,0). What are the coordinates of B' and C'?

B'(2,4) & C'(1,0)

Step-by-step explanation:

According To the Question,

Given, We have an ∆ABC that has coordinates A(3, 1), B(5, 5) and C(4, 1).

Now, After a translation, the coordinates of A' are (0,0) .

Then, the coordinate of B' & C' Also changes the same as like A' .

A(3,1) ⇒ A'(0,0)      {here from x-axis it reduce 3 and from y-axis it reduce 1}

Same as Above,

B(5,5) ⇒ B'(2,4)

&, C(4,1) ⇒ C'(1,0) .

solution:

as, mean is defined as sum of all the observations divided by total number of observations.

and , median is mid value of the data whether arranged in ascending order or descending order.

consider, roadsters:

2,3,4,5,6,7,8,9

mean =

also, median= , because number of observations is even, so median is mean of two mid values.

now, coming to bandits

2,3,4,5,6

mean =  

median = 4, as number of observations is odd.

so, roadsters has greater median as well mean than bandits.

→option a is true about the repairs performed on 2 types of cars:

bandits have lower median and mean than roadsters.