Two buses leave towns 520 kilometers apart at the same time and travel toward each other. One bus travels 16 km/h slower than the other. If they meet in 2 hours, what is the rate of each bus?

122 km/h

138 km/h

Step-by-step explanation:

distance = speed * time

One bus travels 16 km/h slower than the other

(s * 2)  + (s - 16)2 = 520

2s + 2s - 32 = 520

4s = 552

s = 552/4

s = 138 km/h

s - 16 = 122 km/h

option 3 . (5x + 1) - (-10x + 6)

step-by-step explanation:

option 1 :

(4x + 3) + (-9x + 4)

or 4x+3 -9x + 4

or -5x + 7

option 2

(x - 2) - (6x - 9)

or x-2-6x + 9

or -5x + 7

option 3

(5x+ + 6)

or 5x + 1 + 10x -6

or 15x -5

option 4

-4x+2x+7-3x

-7x + 2x + 7

-5x + 7

hence only option 3 did   not satisfy the given simplify expression.