What are the x- and y-intercepts of the graph of y = x2 + 7x + 12? (1 point) x-intercepts: (−3, 0) and (−4, 0) y-intercept: (0, 12) x-intercepts: (−3, 0) and (4, 0) y-intercept: (0, −12) x-intercepts: (3, 0) and (4, 0) y-intercept: (0, −12) x-intercepts: (3, 0) and (−4, 0) y-intercept: (0, 12)

So, the x-intercepts are (-3, 0) and (-4, 0). So, the y-intercept is (0, 12). Thus, the x-intercepts are (-3, 0) and (-4,0). And, y-intercept is (0, 12).

.

Step-by-step explanation:

x-intercept(s):  

(

4

,

0

)

,

(

3

,

0

)

Find the y-intercepts.

Tap for more steps...

y-intercept(s):  

(

0

,

12

)

List the intersections.

x-intercept(s):  

(

4

,

0

)

,

(

3

,

0

)

y-intercept(s):  

(

0

,

12

)

1. 16.64

a^2+b^2=c^2

pr^2=pq^2+qr^2

pr^2=14^2+ 9^2

pr^2=196+81

pr= sqr root of 277

16.64

2. 11.31

c^2-a^2=b^2

18^2- 14^2=b^2

b^2=324-196

b=sqr root of 126

b=11.31

hope it ! (btw im in connections academy to, good luck! )