John bought 8 birds and 6 pigeons for $2400. If he had bought 1 more pigeon and 2 fewer birds, he would have paid $200 more. What is the cost for 1 love bird and 1 pigeon?

1 pigeon is $320

1 love bird is $80

Step-by-step explanation:

Let the cost for 1 love bird be represented by x

Let the cost for 1 pigeon be represented by y.

Since John bought 8 birds and 6 pigeons for $2400. This will be:

8x + 6y = 2400 i

If he had bought 1 more pigeon and 2 fewer birds, he would have paid $200 more. This will be:

6x + 7y = 2600 ii

8x + 6y = 2400 i

6x + 7y = 2600 ii

Multiply equation i by 6

Multiply equation ii by 8

48x + 36y = 14400 iii

48x + 56y = 20800 iv

Subtract iii from iv

20y = 6400

y = 6400/20

y = 320

1 pigeon is $320

From equation i

8x + 6y = 2400

8x + 6(320) = 2400

8x + 1920 = 2400

8x = 2400 - 1920

8x = 480

x = 480/8

x = 60

1 love bird is $80

answer: a. 13/44

step-by-step explanation: judging by the information given to us, we are looking for experimental probability. we can see that 13 males have chosen chocolate ice cream. there are 44 ice creams in total (remember that the total is always the denominator). so our answer is 13/44.

111

step-by-step explanation: