Giải phương trình: 2sin^2x-3cosx+1=0 với-2π

Simplifying

2sin2x + 3cosx + 1 = 0

Reorder the terms:

1 + 3cosx + 2in2sx = 0

Solving

1 + 3cosx + 2in2sx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1' to each side of the equation.

1 + 3cosx + -1 + 2in2sx = 0 + -1

Reorder the terms:

1 + -1 + 3cosx + 2in2sx = 0 + -1

Combine like terms: 1 + -1 = 0

0 + 3cosx + 2in2sx = 0 + -1

3cosx + 2in2sx = 0 + -1

Combine like terms: 0 + -1 = -1

3cosx + 2in2sx = -1

Add '-2in2sx' to each side of the equation.

3cosx + 2in2sx + -2in2sx = -1 + -2in2sx

Combine like terms: 2in2sx + -2in2sx = 0

3cosx + 0 = -1 + -2in2sx

3cosx = -1 + -2in2sx

Divide each side by '3osx'.

c = -0.3333333333o-1s-1x-1 + -0.6666666667in2o-1

Simplifying

c = -0.3333333333o-1s-1x-1 + -0.6666666667in2o-1

Reorder the terms:

c = -0.6666666667in2o-1 + -0.3333333333o-1s-1x-1

Step-by-step explanation:

the answer is 489

step-by-step explanation: