Determine the vertex of the quadratic relation y= 4x2 + 32x – 11

vertex = (- 4, - 75 )

Step-by-step explanation:

Given a quadratic in standard form

y = ax² + bx + c ( a ≠ 0 )

Then the x- coordinate of the vertex is

x = -

y = 4x² + 32x - 11 ← is in standard form

with a = 4, b = 32 , then

x = - = - 4

Substitute x = - 4 into the equation for corresponding y- coordinate

y = 4(- 4)² + 32(- 4) - 11

  = 4(16) - 128 - 11

  = 64 - 139

   = - 75

vertex = (- 4, - 75 )

answer: 2530

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