A set of eight cards contains one joker. Player A chooses 5 cards at random, Player B takes the remaining three cards. What is the probability that Player A has the joker?
Player A discards 4 cards and Player B discards two cards. It is known that the joker has not been discarded, what is the probability that Player A has the joker?

So the first thing we do is to multiply the top equation by 3. the reason i want to do this is i notice there will be a 6y on both equations and can possibly add/subtract them. so we get 6y = -3x + 27. adding that and the second equation we get 6x = 27-15 which is 12. divide by 6 and we get 2. ∴ x = 2. substituting 2 into the first equation we get 2y = -2 + 9 which is 7. divide by 2 and we get 7/2. ∴ y = 7/2, x = 2.