The coordinate plane shows the positions of different places in a town. Each unit on the graph is equal to 1 block. Match the paths with their distances,
10 blocks
7 blocks
9 blocks
13 blocks 16 blocks
from home to the park
to the supermarket
from home to the baseball field
from school to the supermarket
from the park to the supermarket
to the baseball field

Home is located at the point (-5, 5)

The park is located at the point (-2, 3)

Apply the distance formula

When rounding to the nearest whole number, we get 4. This is the approximate distance (in blocks) from home to the park. I'm not sure why "4 blocks" isn't listed as a possible distance, so there may be a typo somewhere.

You'll apply this idea to the other pairs of points to find the other distances.

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

51

step-by-step explanation:

73-22=51 the   mass number minus the amount of protons gives you the amount of neutrons