Can I get some help with this question? I have attempted several times and failed.

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  B.  relative maximum of 8.25 at x=2.5

Step-by-step explanation:

A quadratic of the form ax²+bx+c has an absolute extreme at x=-b/(2a). For your quadratic, that is ...

  x = -5/(2(-1)) = 5/2

The value of the extreme is ...

  f(5/2) = (-5/2 +5)(5/2) +2 = 25/4 +2 = 33/4 = 8.25

The negative leading coefficient tells you the graph opens downward, so the extreme is a maximum.

The function has a relative maximum of 8.25 at x = 2.5.

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A graphing calculator can show this easily.

g = (2, 2)

step-by-step explanation:

given the ratio is 1 : 1 then f is the midpoint of eg

let the coordinates of g = (x, y)

using the midpoint formula

(0 + x) = 1 ( multiply both sides by 2 )

0 + x = 2 ⇒ x = 2

similarly

(4 + y) = 3 ( multiply both sides by 2 )

4 + y = 6 ( subtract 4 from both sides )

y = 2

coordinates of g = (2, 2)