3. If you were to use Gauss-Jordan elimination on the following linear system, what would the augmented matrix be?
3w - X = 2y + 2 - 4
9x - y + z = 10
4w + 3y - 2 = 7
12x + 17 = 2y - Z + 6
O
O
3 -1 -2 -1
9 -1 0 1 10
A.
4 0 3 -1 7
12 -2 1 0 - 11
[3 -1 -2 -1 -4
0 - 1 1 10
B.
4 0 3 -1 7
LO 12-21 -11]
13-12 1-4
o 9 -1 1 10
C.
0 3 -1
0 12 2 -1 6
O
О
3 -1 -2 -1 - 4
0 9-1 1 10
D.
4 0 3 -1 7
0 12 2 1 6

starting with:    

5 + x - 12 = 2x - 7   

5 + x - 12 - x = 2x - 7 - x (subtract x from both sides)   

5 - 12 = x - 7 (combine and cancel x's from both sides)   

5 - 12 + 7 = x - 7 + 7 (add 7 to both sides)   

0 = x (add numbers together on both sides)       

so in order for the equation to be true, x must be 0.   

trying x = -0.5   

5 + x - 12 = 2x - 7 (original equation)   

5 + -0.5 - 12 = 2(-0.5) - 7 (plug in value of x)   

5 + -0.5 - 12 = -1 - 7 (did multiplication)   

-7.5 = -8 (did addition on both sides)       

since -7.5 is obviously not equal to -8, the value of -0.5 for x is wrong.   

trying x = 0   

5 + x - 12 = 2x - 7 (original equation)   

5 + 0 - 12 = 2(0) - 7 (plug in value of x)   

5 + 0 - 12 = 0 - 7 (did multiplication)   

-7 = -7 (did addition on both sides)       

since -7 equals -7, that demonstrates that the value of 0 for x is correct.   

trying x = 1   

5 + x - 12 = 2x - 7 (original equation)   

5 + 1 - 12 = 2(1) - 7 (plug in value of x)   

5 + 1 - 12 = 2 - 7 (did multiplication)   

-6 = -5 (did addition on both sides)       

since -6 is obviously not equal to -5, the value of 1 for x is wrong.

what are the statments

step-by-step explanation:

sorry i just need to anwers this to get points

step-by-step explanation: