Isabella had a big bag of sweets, she ate two fifth of them on Monday, two fifth of those remaining on Tuesday, and two thirds of what remaining on Wednesday. She then had 12 sweets. How many were in the bag originally?

100 sweets

Step-by-step explanation:

Let initial number of sweet = x

Monday :

2/5 of x = 2x/5

Number left = x - 2x/5 = 3x/5

Tuesday :

2/5 of remaining = 2/5 * 3x/5 = 6x/25

Number left = 3x/5 - 6/25 = 9x/25

Wednesday :

2/3 of remaining = 2/3 * 9x/25 = 18x/75

Number left = 9x/25 - 18x/75 = 9x / 75

9x/75 corresponds to 12

9x/75 = 12

Cross multiply :

9x = 12 * 75

9x = 900

x = 900 / 9

x = 100 sweets

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions

amount of oatypop that contains the prize = 40%

amount   of oatypop which doesn't contain the prize = (100-40)=60%

probability that hannah will win a prize

    = s +f s +f f s+ff   f s+ff f f s+ infinity.where f= failure,s= success

=   or 60%

probability that hannah only has to buy 3 or less boxes before getting a prize= (s) and ( f s) and (ff s) and (f f f s)

        = = 87.04 %  

step-by-step explanation: