Consider the frequency distribution below, which has single values as classes: Value Frequency 10 11 12 13 14 15 16 17 18 19 20 21 1 3 7 18 10 4 2 7 16 10 6 2 Construct a new frequency distribution for this data with 4 classes.

The original table (attached to this response) shows single values as classes.

To construct a new frequency distribution for this data with 4 classes, follow these steps:

i. Starting from the least value (which is 10) create groups each of 4 values. For example, the first group will contain 10, 11, 12 and 13. Therefore, we have a class of 10 - 13.

The second group will contain 14, 15, 16 and 17. Therefore, we have a class of 14 - 17

The third group will contain 18, 19, 20 and 21. Therefore, we have a class of 18 - 21

ii. Get the frequency of these classes, we add the frequencies of the members of the class.

For example,

Class 10 - 13 will have a frequency of (1 + 3 + 7 + 18) = 29

Class 14 - 17 will have a frequency of (10 + 4 + 2 + 7) = 23

Class 18 - 21 will have a frequency of (16 + 10 + 6 + 2) = 34

The new table has been attached to this response.

the answer to your question a or b but i am pretty sure it is b. i hope this : )

step-by-step explanation:

ca = ec

cpctc makes it so that corresponding parts of the triangle you proved to be equal are equal, the other options aren't part of the part of the triangles you proved to be equal.