statisticians for a roadside assistance company interviewed 50{,}00050,00050, comma, 000 randomly selected United States (US) households. Of those, 15{,}59515,59515, comma, 595 reported that they had traveled 505050 or more miles from home between December 232323 and January 444. If there are 115{,}000{,}000115,000,000115, comma, 000, comma, 000 US households, approximately how many of them do the interviews suggest traveled 505050 or more miles from home at that time

The answer is "35,868,500 people".  

Step-by-step explanation:

In this question, the chance of people that have traveled above 50 miles is calculated. The chance of success is the probability.

The population of the United States is at 1150000.

Let's determine that portion of the current population has gone more than 50 miles:

since your problem is x^4 = 81, what you have to undeo is the "to the fourth power" part.

the inverse (opposite operation) of "to the fourth power" is "to the fourth root".

  (x^4) ^ ¼   = 81 ^ ¼  

  81 = 3^4     so (3 ^ 4) ^ ¼   =   3 ^ 1   = 3

by hand: (3 ^ 4) ^ ¼   =   3 ^ (4 x ¼) = 3 ^ 1   = 3   (when you take a power to a power, multiply the exponents.)

or, do it by calculator. one way of finding the fourth root is to use ^ (1/4)

step-by-step explanation:

understand that i don't know the answers

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