Find the domain of f/g f(x)= sqrt 4-x^2 g(x)= sqrt 3x+4

(-4/3, 2]

Step-by-step explanation:

f(x)= sqrt (4-x^2)

g(x) = sqrt (3x+4)

domain of f(x)/ g(x)

The domain of the numerator is

4-x^2 ≥ 0

4 ≥x^2

Taking the square root of each side

-2 ≤x≤2

The domain of the denominator

3x+4 > 0  ( the denominator cannot be zero)

3x>-4

x > -4/3

Combine the restrictions to make it most restrictive

-4/3<x≤2

In interval notation

(-4/3, 2]

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

answer: a.

step-by-step explanation: the answer is a. because, you need to converge the fractions to find a solution.