Given that x = 4, b=6 and c = 3. Then 3a + bc = 16. 

true or false?​

False

Step-by-step explanation:

3a + bc = 16.

Let a=4 b=6 c=3

3(4) + 6*3 = 16

Multiply

12+18 =16

30 = 16

False

False!

Step-by-step explanation:

There is no a variable that is given, though I'm going to assume you mean that x=4 is supposed to be a=4. If I'm mistaken, there isn't much to say about whether the statement is true or false, because there's no false statement as it'd give you a=? and you can't prove or disprove this information without more information.

If my assumption is correct, we'll first start solving this problem by substituting in the variables, which would give us: 3(4)+(6)(3)=16

Then, we'll evaluate 3(4) first, because of order of operations, which gives us 12. To reiterate the problem, we now have: 12+(6)(3)=16 From here, we can already tell this is going to be a false statement, as there is no way 6 times anything but zero will give a sum less than 6, but if you didn't catch that, we can continue with our next step.

Evaluate (6)(3) in order to get 18, in order to get: 12+18=16

And finally, we'll add. 12+18 is 30, which as we know, is not equal to 16, so that makes this statement false. 30≠16

answer: this doesnt make any sense especially the photo.

step-by-step explanation:

y < -3

step-by-step explanation:

-3y - 2 > 7

-3y -2 + 2 > 7+2

-3y > 9

-3y/-3 < 9/-3   (change the inequality sign when multiplying or dividing by a negative number)

y < -3