PLWASE HELP PLEASE PLEASE

66 in^2

Step-by-step explanation:

Imagine that the figure is a whole square, where the space between is filled in.

Find the area of the imaginary square (l x w):

9 in. x 9 in. = 81 in^2

Lets make that whole square the original figure it used to be (take away the space we “filled in”)

Lets find the area of the space we filled in:

5 in x 3 in= 15 in^2

Subtract the imaginary square’s area by the area of the space that was originally blank:

81 in^2 - 15 in^2 = 66 in^2

66 in^2 IS YOUR FINAL ANSWER, that is the real area of the composite figure you have.

Hope this helps!

46.2+112.3

step-by-step explanation:

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°