NEED HELP WITH THIS PLEASE. Just show me how please.

Given:

The quadratic equation is:

To find:

The discriminant of the given equation and the number of real solutions.

Solution:

If a quadratic equation is , then the value of discriminant is:

If D<0, then the quadratic equation has no real roots or two imaginary roots.

If D=0, then the quadratic equation has two equal real roots.

If D>0, then the quadratic equation has two distinct real roots.

We have,

Here, . So, the discriminant of the given equation is:

Since D<0, therefore the number of real solutions is 0.

Hence, the value of the discriminant is -31 and the number of real solutions is 0.

3. (5x + 1) - (-10x + 6)

simplify the answer choice. combine like terms. remember to distribute the negative to the terms inside the second parenthesis. also remember that two negatives = one positive, and one of each sign = negative.

- (-10x + 6) = + 10x - 6

simplify. combine like terms:

5x + 1 + 10x - 6

5x + 10x + 1 - 6

15x - 5

∴ it is your answer

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ca = ec

cpctc makes it so that corresponding parts of the triangle you proved to be equal are equal, the other options aren't part of the part of the triangles you proved to be equal.