Please help show steps thx

1) P = 282m, A = 141m^2

2) P = 82.4in, A = 40in^2

3) P = 62.7m, A = 73.1m^2

Step-by-step explanation:

1) top:L=12m, W=3m, mid: l= 12m, w= 12-7 = 5m, bot: l=15m, w=3m

Perimeter= 2(lw)

P = 2(12x3) + 2(12x5) + 2(15x3)

P = 2(36) + 2(60) + 2(45)

P = 72 + 120 + 90

P = 282m  

Area= lw

A = (12x3) + (12x5) + (15x3)

A = 36 + 60 + 45

A = 141m^2

2) Rectangle:l=7in, w=5in, Right Triangle:a=5-3=2in, b=12-7=5in

Perimeter= 2(lw) + (a+b+sqrt(a^2+b^2))

P = 2(7x5) + (2+5+sqrt(2^2+5^2))

P = 70 + 12.39

P = 82.4in

Area= lw + ((ab)/2)

A = (7x5) + ((2x5)/2)

A = 35 + 5

A = 40in^2

3) Semi-Circle: d=8m, r=8/2=4m, Right Triangle: a=8m, b=12m

Perimeter= pid + (a+b+sqrt(a^2+b^2))

P = 9pi + (8+12+sqrt(8^2+12^2))

P = 28.27 + 34.42

P = 62.7m

Area= (1/2)pir^2 + ((ab)/2)

A = (1/2)pir^2 + ((ab)/2)

A = (1/2)pi(4)^2 + ((8x12)/2)

A = 25.13 + 48

A = 73.1m^2

80x^8−68x^6+16^5−20x^4−4x^3+8x^2

hope i'm right lol

system of linear equation

step-by-step explanation:

as given in the data

a= 20 , b= -12

let us suppose that it is a straight line equation

now we know the formula for the system of linear equation

b= ma + c )

here m is slope of a straight line which is equal to formula

m=   (ii)

and here c is a constant

now putting the value of a and b in equation (ii)

m=

m=

putting the value of a,b and m in equation (i) gives us

-12 = + c

-12=-12 + c

adding 12 to both sides

-12 +12 = -12 +12 +c

0 =c

or c=0

as the value of the constant is zero which gives us that it is a linear equation and this order pair satisfies the system of linear equations.