An object is kept at a distance of 15 cm from each of the above lens calculate the image distance and magnification o f first image​

answer is

Step-by-step explanation:

Object distance (u) = -100cm  Focal length (f) = 50cm Image distance = v  By lens formula; 1v−1u=1f1v−1u=1f ⇒ 1v−1−100=1501v−1−100=150 ⇒1v=150−11001v=150−1100 ⇒1v=2−1100−11001v=2−1100−1100 v =100cm  Hence the image is formed at 100 cm behind the lens.  Object distance (u) = -100cm  Focal length (f) = -25cm  Image distance = v  By lens formula;Read more on Sarthaks.com - https://www.sarthaks.com/951256/an-object-is-kept-at-a-distance-of-100-cm-from-each-of-the-above-lenses-calculate-the?show=951265#a951265

step-by-step explanation:

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.